Answer:
Step-by-step explanation:
Q = m c Δt
heat withdrawn to lower temperature by 40° C
Q = 1 X 1000 X 40 = 40,000 calories.
Q = mL
heat withdrawn to freeze water at 0°C to ice
= 1 x 80000 = 80,000 calories
total heat to be withdrawn = 120,000 calories. = 120,000 x 4.2 = 504 ,000 Joules.