Answer:
![y = - (3)/(20) {x}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1p4nt4vswboxwljrvjqvfftht39fgs9rvf.png)
Explanation:
The given parabola has focus at:
![(0, - (5)/(3) )](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4vkuqf9wd82m8lawfneflr2zr85x6dobvb.png)
and directrix at
![y = (5)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/so32pwohnbh6a7w347obu095wmnx2rc7lu.png)
This is a vertical parabola that opens downwards.
The equation is of the form;
![{x}^(2) = - 4py](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2yz4k9100izgmreh3q99ysqsai66yy694k.png)
p is the distance from the vertex to the directrix.
Since the vertex is at the origin, we have
![p = (5)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vr2p69905qilkv3o9i4lbjbqslke7esa8g.png)
We plug this value into the equation to get:
![{x}^(2) = - 4( (5)/(3) )y](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1wz4pg1xup4e4s27so03oma0jjmiyix9dl.png)
![{x}^(2) = - (20)/(3) y](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9wrqitigwvsqsn6wxq1tk3lmqglnzfybju.png)
We solve for y to obtain:
![y = - (3)/(20) {x}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1p4nt4vswboxwljrvjqvfftht39fgs9rvf.png)
The 3rd option is correct.