Question

Probability of multiple Events
A.
B.
C.
D.

Answer 1

Given that
`P(Q)=(3)/(5),P(R)=(1)/(3)`

Also,

`P(Q\wedge R)=P(Q)\cdot P(R)=(3)/(5)\cdot(1)/(3)=(1)/(5)`

We can conclude that,

`P(Q\vee R)=P(Q)+P(R)=(3)/(5)+(1)/(3)=\boxed{(14)/(15)}`

The answer is B.

Hope this helps.

r3t40