Question

Please help, Show all work!

Answer 1

So it's given that <ABC = 90°

and <ABD is 5times <DBC, from this information:

it's understood that there are 6 portions of <DBC all together inside the whole 90°.

so 1st divide 90° ÷ 6 = 15°

therefore the angle <DBC = 15°

(5 of 15° angles inside <ABD and one of 15° angle as <DBC)

Answer 2

The whole measure of 90 degrees is split into 2. If one of the measures is 5 times the measure of the other one, then we have to divide 90/6 5 )times the measure + the other measure ). We get 15 so measure is 15 and ABD is 15x5 which is 75. 15+75=90