Question

Helpp please!!!

Arrange the functions according to the positions of their horizontal asymptotes on the coordinate plane, starting with the lowest and ending with the highest.

Answer 1

The photo is blurry but it shows the answer is CORRECT. The correct sequence is,

h

j(x)=3x^2-x+1 / 1-x^2

f

g

j(x)=2x^2-3x+17 / (x-5)^2

i

k

l

Explanation:

In case you found the above answer confusing, here is this !! Hope I could help :)

Answer 2

h, j2, f, g, j1, i, k, l (ell)

Explanation:

The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).

We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).

The horizontal asymptotes are ...

• h(x): 16x/(-4x) = -4
• j1(x): 2x^2/x^2 = 2
• i(x): 3x/x = 3
• l(x): 15x/(2x) = 7.5
• g(x): x^2/x^2 = 1
• j2(x): 3x^2/-x^2 = -3
• f(x): 0x^2/(12x^2) = 0
• k(x): 5x^2/x^2 = 5

So, the ordering least-to-greatest is ...

h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)