Question

What do I do to solve this problem?

Answer 1

D

Explanation:

Consider one of the circles

the area (A) of the sector is calculated as

A = area of circle × fraction of circle

Since ΔHPU is equilateral then ∠HPU = 60°, thus

A = πr² ×
`(60)/(360)`

= π × 3² ×
`(1)/(6)`

= 9π ×
`(1)/(6)` =
`(3)/(2)` π

Shaded area = area of circle - area of sector = 9π -
`(3)/(2)` π =
`(15)/(2)` π

Since both circles are congruent then

total shaded area = 2 ×
`(15)/(2)` π = 15π → D