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How do I find the value of x in this equation
4 – 5(x + 3) = 2

User Padavan
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2 Answers

3 votes

Answer:


\displaystyle4-5\left(x+3\right)=2\quad :\quad x=-(13)/(5)\quad \left(\mathrm{Decimal}:\quad x=-2.6\right)

Explanation:


4-5\left(x+3\right)=2


\gray{\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}}


4-5\left(x+3\right)-4=2-4


\gray{\mathrm{Simplify}}


-5\left(x+3\right)=-2


\gray{\mathrm{Divide\:both\:sides\:by\:}-5}


\displaystyle(-5\left(x+3\right))/(-5)=(-2)/(-5)


\gray{\mathrm{Simplify}}


\displaystyle x+3=(2)/(5)


\gray{\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}}


\displaystyle x+3-3=(2)/(5)-3


\gray{\mathrm{Simplify}}


\displaystyle x=-(13)/(5)

How do I find the value of x in this equation 4 – 5(x + 3) = 2-example-1
User FTWinston
by
7.8k points
6 votes


</p><p>4-5(x+3)=2 \\</p><p>4-5x-15=2 \\</p><p>4-5x-15+15=2+15 \\</p><p>4-5x=17 \\</p><p>4-5x-4=17-4 \\</p><p>-5x=13 \\</p><p>-5x\cdot(-1)=13\cdot(-1) \\</p><p>5x=-13 \\</p><p>5x/5=-13/5 \\</p><p>x=\boxed{-(13)/(5)}</p><p>

Hope this helps.

r3t40

User Tronics
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