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How do I solve this problem?

How do I solve this problem?-example-1

1 Answer

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Answer:

C

Explanation:

Since AC is a tangent at C then ∠ACB = 90 and ΔABC is right

The area A of ΔABC = 0.5 × BC × AC ( A = 0.5 bh )

Calculate AC using Pythagoras' identity

The square on the hypotenuse AB is equal to the sum of the squares on the other 2 sides, that is

AC² + BC² = AB², substitute values

AC² + 4² = 8², that is

AC² + 16 = 64 ( subtract 16 from both sides )

AC² = 48 ( take the square root of both sides )

AC =
√(48) =
√(16) ×
√(3) = 4
√(3), hence

Area of ΔABC = 0.5 × 4 × 4
√(3) = 8
√(3) → C

User Pranav Kumar H M
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