Question 1

Cual es la respuesta de (x10+10y12) al cuadrado

Question 2

Answer:

$\mathrm{Expand}\:\left(x^(10)+10y^(12)\right)^2:\quad x^(20)+20x^(10)y^(12)+100y^(24)$

Explanation:

$\left(x^(10)+10y^(12)\right)^2$

$\gray{\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2}$

$\gray{a=x^(10),\:\:b=10y^(12)}$

$=\left(x^(10)\right)^2+2x^(10)\cdot \:10y^(12)+\left(10y^(12)\right)^2$

$\black{\mathrm{Simplify}\:\left(x^(10)\right)^2+2x^(10)\cdot \:10y^(12)+\left(10y^(12)\right)^2:}$

$\left(x^(10)\right)^2+2x^(10)\cdot \:10y^(12)+\left(10y^(12)\right)^2$

$\gray{\left(x^(10)\right)^2=x^(20)}$

$\gray{2x^(10)\cdot \:10y^(12)=20x^(10)y^(12)}$

$\gray{\left(10y^(12)\right)^2=100y^(24)}$

=x^(20)+20x^(10)y^(12)+100y^(24)

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