1 Answer

Pranav Raj · Answer 1 · 2020-01-08T05:48:20+0000

$\huge{\boxed{6(h+8)}}$

First, find the factors of 6 and 48.

6: 1, 2, 3, 6

48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The greatest factor they have in common is
. Factor it out of
6h+48 by dividing each term by
.
$\boxed{6(h+8)}$

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