Answer:
2-square root 3, 2+ square root 3
Explanation:
If the polynomial has rational and real coefficients, the roots will be "conjugates" of each other. That is, the sum of the root should be a rational number. So, the irrational parts will be opposites, while the rational parts remain the same.
2±√3 . . . can be the roots of p(x) when p(x) has rational real coefficients