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Given a polynomial p(x)=0, which two expressions could be a pair of irrational roots of the equation square root 2-3, 2-square root 3, square root 3-2, 2+ square root 3, -square root 2+3 please help!

User Shifenis
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1 Answer

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Answer:

2-square root 3, 2+ square root 3

Explanation:

If the polynomial has rational and real coefficients, the roots will be "conjugates" of each other. That is, the sum of the root should be a rational number. So, the irrational parts will be opposites, while the rational parts remain the same.

2±√3 . . . can be the roots of p(x) when p(x) has rational real coefficients

User Daniel Wu
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