Given the points (–3,k) and (2,0), for which values of k would the distance between the points be √34 ?

Question

asked Dec 4, 2020 184k views

2 Answers

Miroslav Prymek · Answer 1 · 2020-12-09T02:29:09+0000

Answer:

The values of k are 3 and -3

Explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}$

we have

$(-3,k)\\(2,0)$

d=√(34)

substitute

$√(34)=\sqrt{(0-k)^(2)+(2+3)^(2)}$

$√(34)=\sqrt{(-k)^(2)+(5)^(2)}$

$√(34)=\sqrt{k^(2)+25}$

squared both sides

34=k^(2)+25

k^(2)=34-25

k^(2)=9

k=(+/-)3