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If the sum of three consecutive numbers is 36. Find the numbers.

User Ludovic
by
8.1k points

2 Answers

3 votes

Answer:

11, 12, 13

Explanation:

x is the first number

(x + 1) is the second number

(x + 2) is the third number

x + x+1 + x+2 = 36

3x + 3 = 36

3x = 36 - 3

3x = 33

x = 11 ← the first number

the second number = x + 1 = 11 + 1 = 12

the third number = x + 2 = 11 + 2 = 13

User Turako
by
7.9k points
3 votes


\huge{\boxed{11}}\ \ \huge{\boxed{12}}\ \ \huge{\boxed{13}}

First, represent the numbers with variables.
x is the first number.
x+1 is the second number, since they are consecutive.
x+2 is the third and final number.

Make a statement.
x+x+1+x+2=36

Combine the variables.
3x+1+2=36

Combine the constants.
3x+3=36

Isolate the variable by subtracting
3 on each side.
3x=33

Finish isolating the variable by dividing both sides by
3.
x=11

This means the first number is
\boxed{11}. Since the three numbers are consecutive, the other two numbers are
\boxed{12} and
\boxed{13}.

We can then check out work by adding these three numbers together. If they equal
36, then the answer is correct.
11+12+13=36

Add
11 and
12.
23+13=36

Add
23 and
13.
36=36

This means our answer is correct.

User Voltento
by
7.6k points

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