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What is the distance between P(12, 4) and Q(-8, 2)

User Mfluehr
by
8.4k points

2 Answers

2 votes

Answer:
2√(101)

Explanation:

The distance between two points can be calculated with the following formula:


d=√((x_2-x_1)^2+(y_2-y_1)^2)

Given the points P(12, 4) and Q(-8, 2), we can identify that:


x_2=-8\\x_1=12\\y_2=2\\y_1=4

Then, substituing values into the formula, we get that the distance between these two points is:


d_((PQ))=√((-8-12)^2+(2-4)^2)\\\\d_((PQ))=2√(101)

User Hoyen
by
8.4k points
3 votes


\huge{\boxed{2 √(101)}}

The distance formula is
√((x_2-x_1)^2+(y_2-y_1)^2), where
(x_1, y_1) and
(x_2, y_2) are the points.

Substitute in the points.
√((2-4)^2+(-8-12)^2)

Subtract.
√((-2)^2+(-20)^2)

Solve the exponents.
√(4+400)

Add.
√(404)

Now, we can simplify this square root just a little bit.
404 has a square factor of
4.
√(404)=√(4)*√(101)

The square root of
4 equals
2.
\boxed{2 √(101)}

User Lordofthejars
by
8.8k points

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