Answer: 0.3929
Explanation:
Given : The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 7 minutes.
The probability density function :-
![f(x)=(1)/(7-0)=(1)/(7)](https://img.qammunity.org/2020/formulas/mathematics/college/za5olnt2iwt48gzjwh4xh16bwer13koa5o.png)
The interval of probability distribution of success event = [4.25,7] =
![7-4.25=2.75](https://img.qammunity.org/2020/formulas/mathematics/college/fsmfy0hmud02bga88uucie6n6d21ejm4pp.png)
Then , the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes is given by :-
![(2.75)/(7)=0.39285714\approx0.3929](https://img.qammunity.org/2020/formulas/mathematics/college/521bw7uex1tu2w6hytf45euo13hsbr099v.png)