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Find a such that the solution of y'' + y' − 2y = 0, y(0) = a, y' (0) = 1 tends to zero as t → +∞.

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Answer:

Explanation:


y'' + y' − 2y = 0, y(0) = a, y' (0) = 1

Auxialary equation is


m^2+m-2=0\\m=-2,1

General solution is


y=Ae^(-2x) +Be^x


y(0) = A+B =a


y'(0) = -2Ae^(2x) +Be^x = -2A+B = 1

Eliminate B to get

3A =a-1

We know that y tends to 0 when x tends to infinity for any finite A

i.e. a should be a finite real number.

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