Question

3x+4y^2=7z (solve for y)

Answer 1

`y = + - \sqrt{ (7)/(4) } z - (3)/(4) x`

Explanation:

`3x + 4y^(2) = 7z`

`4y^(2) = 7z - 3x`

Divide both sides by 4

`{y}^(2) = (7)/(4) z - (3)/(4) x`

`\sqrt{ {y}^(2) } = \sqrt{ (7)/(4) } z - (3)/(4) x`

Final answer:

`y = + - \sqrt{ (7)/(4) } z - (3)/(4) x`