Question

Wavelength The crystal field splitting in Cr(CN)6]3-is Д,-5.51 x 10-19 J. At what wavelength will the [Cr(CN on absorb light most strongly (in nm)? constants: Planck's constant h = 6.626 × 10-34 J·s, speed of light c = 2.998 × 108 m/s

Answer 1

Answer : The wavelength will be, 360.5 nm

Explanation :

Formula used :

`\Delta_o=(h* c)/(\lambda)`

where,

`\Delta_o` = crystal field splitting energy =
`5.51* 10^(-19)J`

h = Planck's constant =
`6.626* 10^(-34)Js`

c = speed of light =
`2.998* 10^8m/s`

`\lambda` = wavelength = ?

Now put all the given values in the above formula, we get:

`5.51* 10^(-19)J=((6.626* 10^(-34)Js)* (2.998* 10^8m/s))/(\lambda)`

`\lambda=3.605* 10^(-7)m=360.5* 10^(-9)m=360.5nm`

conversion used :
`(1nm=10^(-9)m)`

Therefore, the wavelength will be, 360.5 nm