Question

A horizontal power line carries a current of 5960 A from south to north. Earth's magnetic field (77.6 µT) is directed toward the north and is inclined downward at 70.0° to the horizontal. Find the (a) magnitude and (b) direction of the magnetic force on 91.0 m of the line due to Earth's field.

Answer 1

Step-by-step explanation:

It is given that,

Current flowing, I = 5960 A

Magnetic field,
`B=77.6\ \mu T=77.6* 10^(-6)\ T`

1. Angle between Magnetic field and horizontal is 70°. We need to find the magnetic force on 91.0 m of the line due to Earth's field. Magnetic force is given by :

`F=ILB\ sin\theta`

`F=5960* 91* 77.6* 10^(-6)* sin(70)`

F = 39.54 N

2. The direction of magnetic force can be calculated using Fleming's left hand rule, the direction of magnetic force is in west direction.