Question

Sapting Leng You have a string with a mass of 13.7 q. You stretch the string with a force of 8.39 N, giving it a length of 1.87 m. Then you vibrate the string transversely at precisely the frequency that corresponds to its fourth normal mode, that is, at its fourth harmonic. What is the wavelength of the standing wave you create in the string? What is the frequency? Wavelength Number Frequency: Number Hz

Answer 1

a)
`\lambda=0.935\ \textup{m}`

b)
`f=36.19\approx 36\ \textup{Hz}`

Step-by-step explanation:

Given:

String vibrates transversely fourth dynamic, thus n = 4

mass of the string, m = 13.7 g = 13.7 × 10⁻¹³ kg

Tension in the string, T = 8.39 N

Length of the string, L = 1.87 m

a) we know

`L= n(\lambda)/(2)`

where,

`\lambda` = wavelength

on substituting the values, we get

`1.87= 4* (\lambda)/(2)`

or

`\lambda=0.935\ \textup{m}`

b) Speed of the wave (v) in the string is given as:

`v =f\lambda`

also,

`v=\sqrt(T)/(((m)/(L)))`

equating both the formula for 'v' we get,

`f\lambda=\sqrt(T)/(((m)/(L)))`

on substituting the values, we get

`f* 0.935=\sqrt(8.39)/(((13.7* 10^(3))/(1.87)))`

or

`f=(33.84)/(0.935)`

or

`f=36.19\approx 36\ \textup{Hz}`