Question

NEED HELP PLEASE!

A ride at an amusement park has two options for cars, one that holds 6 passengers and one that holds 3 passengers. If the ride designer wants to make sure that each run holds at least 12 passengers, which graph shows the possible combinations of the number of 6-passenger cars, x, and the number of 3-passenger cars y?

Answer 1

yep i agree it's the 4th one i took the test and i got that one correct

Explanation:

Answer 2

Answer: Fourth option is correct.

Explanation:

Since we have given that

Number of passengers for first car can hold = 6

Number of passengers for second car can hold = 3

According to question, If the ride designer wants to make sure that each run holds at least 12 passengers.

Let the number of 6 passengers cars be 'x'.

Let the number of 3-passengers cars be 'y'.

So, our equation becomes,

`6x+3y\geq 12\\\\2x+y\geq 4`

Put x = 0, y= 0

So, it becomes 0≥4 which is false.

So, it is shaded away from the origin.

At x= 0, y≥4

at y = 0, x≥6

Hence, Fourth option is correct.