Question

Part A If a sample of gold having a mass of 27.63 g is pressed into a thing foil of 1,000 mierometer thickness, then what is the area of the foi? The density of gold is 19.32 g/cm3

Answer 1

The area of the gold foil is
`14.3 cm^(2)`

Step-by-step explanation:

Mass of gold foil , m= 27.63 g

Thickness of gold foil ,
`t=1000\mu m=0.1 cm`

Density of gold ,
`\rho =19.32(g)/(cm^(3))`

Let the area of gold foil be A then the total volume of gold foil is given by

`V=At=(m)/(\rho )`

=>
`A=(m)/(t\rho )=(27.63)/(0.1* 19.32) cm^(2)`

=>
`A=14.3 cm^(2)`

Thus the area of the gold foil is
`14.3 cm^(2)`