Question

Walk then Run Compute your average velocity in the following two cases You walk for 1.21 min at a speed of 1.22 m/s and then run for 1.21 min at 3.05 m/s along a straight track.

Answer 1

2.135 m/s

Step-by-step explanation:

T₁ = Time taken for first walk = 1.21 min = 1.21×60 = 72.6 s

V₁ = Velocity for first walk = 1.22 m/s

T₂ = Time taken for second walk = 1.21 min = 1.21×60 = 72.6 s

V₂ = Velocity for second walk = 3.05 m/s

Displacement travelled in first walk

S₁ = V₁×T₁

⇒S₁ = 1.22×72.6

⇒S₁ = 88.572 m

Displacement travelled in second walk

S₂ = V₂×T₂

⇒S₂ = 3.05×72.6

⇒S₂ = 221.43 m

Total displacement = 88.572+221.43 = 310.002 m

Total time = 72.6+72.6 = 145.2

`\text{Average Velocity}=\frac{\text{Total displacement}}{\text{Total time}}\\\Rightarrow \text{Average Velocity}=(310.002)/(145.2)\\\Rightarrow \text{Average Velocity}=2.135\ m/s`

∴ Average velocity in this case is 2.135 m/s