Question

Write an equation in slope-intercept form for the line passing through the pair of points.

(-1, 2), (4, -3)

A) y = -x + 1
B) y = 0x - 1
C) y = -x - 1
D) y = 0x + 1

Answer 1

A line in form of y = ax + b passes (0, 2)

=> 2 = 0x + b => b = 2

This line also passes (4, 6)

=> 6 = 4x + 2 => x = 1

=> Equation of this line: y = x + 2

=> Option C is correct

Hope this helps!

:)

Explanation:

Answer 2

A) y= -x + 1

Explanation:

The slope-intercept form of an equation of a line:

`y=mx+b`

m - slope

b - y-intercept

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

==========================================

We have the points (-1, 2) and (4, -3).

Calculate the slope:

`m=(-3-2)/(4-(-1))=(-5)/(5)=-1`

Put the value of the slope an the coordinates of the point 9-1, 2) to the equation of a line:

`2=(-1)(-1)+b`

`2=1+b` subtract 1 from both sides

`1=b\to b=1`

Finally:

`y=-x+1`