Question

An initially evacuated 1.5 m tank is fed (adiabatically) with steam from a line available at a constant 15 MPa and 400 °C until the tank pressure reaches 15 MPa. What is the final mass of water in the tank in kg?

Answer 1

95.8 kg

Step-by-step explanation:

At the end of the feeding process, there is steam in the tank at 15 MPa and 400ºC because the process is adiabatic. So, use the steam tables (In this case I use data from van Wylen Six Edition, table B.13) in order to get the specific volume of superheated steam.

The specific volume data reported is
`v=0.01565(m^(3))/(kg)`

The mass can be calculated with the definition of specific volume:

`v=(V)/(m)\\m=(V)/(v)=(1.5m^(3))/(0.01565(m^(3))/(kg)) =95.8kg`