Question

A steam heat engine is used to supply 14600 hp of power to a nearby city. The heat engine has a thermal efficiency of 33%. What is the rate of heat rejection by this heat engine?

Answer 1

34066.6 hp

Step-by-step explanation:

We have given efficiency=33%=0.33

`efficiency=(W)/(Q_1)`

`Q_1=(W)/(efficiency)`

`Q_1=(14600)/(0.33)=44242.4242\ hp`

we know that
`W=Q_1-Q_2`

`Q_2=Q_1-W`

=44242.4242-14600=29642.4242HP

so the value of
`Q_2` the rate of heat of rejection is 29642.4242 hp