Question

A vehicle of 1 200 kg is moving at a speed of 40 km/h on an incline of 1 in 50. The total constant rolling and wind resistance is 600 N. The efficiency of the drive from the engine trough the gearbox to the wheels is 80 % and the gear ratio causes a final engine to wheel velocity ratio of 4:1. The effective wheel diameter is 500 mm. Calculate the engine power to maintain this speed.

Answer 1

Answer:11.602 KW

Step-by-step explanation:

mass of vehicle
`\left ( m\right )=1200 kg`

speed=40Km/h

Resistance=600 N

`\eta =80%`

Gear ratio
`\left ( G\right )=4:1`

`D_(effective)=500mm`

Net force to overcome by engine is

F=Resistance + sin component of weight

F=600+
`mgsin\theta`

Where
`tan\theta =[tex](1)/(50)`

`\theta =1.1457^(\circ)`

`F=600+1200* 9.81* sin\left ( 1.1457\right )`

F=600+235.38=835.38 N

power=
`F.v=835.38(100)/(9)`

Engine Power=
`(835.(100)/(9))/(\eta )`=11.602 KW