Question

A rigid tank initially contains 2 kg of steam at 500 kPa and 350°C. The steam is then cooled until it is at 100°C. Determine the final pressure and the heat transferred during this process.

Answer 1

299.36 kPa

Step-by-step explanation:

given mass of steam =2 kg

initial pressure that is
`P_1=500kPa`

initial temperature that is
`T_1=350^(\circ) C=350+273=623 K`

final temperature that is
`T_2=100^(\circ) C=100+273=373 K`

it is a rigid tank so volume is constant

for constant volume process
`(P_1)/(T_1)=(P_2)/(T_2)`

`P_2=(T_2)/(T_1)* P_1=(373)/(623)* 500=299.36 kPa`

so the final pressure will be 299.36 kPa