181k views
1 vote
Consider an open loop 1-degree-of-freedom mass-spring damper system. The system has mass 4.2 kg, and spring stiffness of 85.9 N/m, and damping coefficient of 1.3 N.s/m. What is the non-dimensional damping ratio of the system? Use at least 4 significant digits after the decimal point.

1 Answer

5 votes

Answer:

Damping ratio
\zeta =0.0342

Step-by-step explanation:

Given that

m=4.2 kg,K=85.9 N/m,C=1.3 N.s/m

We need to find damping ratio

We know that critical damping co-efficient


C_c=2\sqrt {mk}


C_c=2\sqrt {4.2* 85.9}


C_c=37.98 N.s/m

Damping ratio(
\zeta) is the ratio of damping co-efficient to the critical damping co-efficient

So
\zeta =(C)/(C_c)


\zeta =(1.3)/(37.98)


\zeta =0.0342

So damping ratio
\zeta =0.0342

User Plancys
by
5.3k points