Question

A 2-cm-diameter vertical water jet is injected upward by a nozzle at a speed of 15 m/s. Determine the maximum weight of a flat plate that can be supported by this water jet at a height of 2 m from the nozzle. Take the density of water to be 1000 kg/m3 The maximum weight of a flat plate that can be supported by the water jet is____ N.

Answer 1

Answer:58.28 N

Step-by-step explanation:

Given data

`dia. of nozzle \left ( d\right )=2 cm`

`initial velocity\left ( u\right )=15 m/s`

`height\left ( h\right )=2m`

Now velocity of jet at height of 2m

`v^2-u^2=2gh`

`v^2=15^2-2\left ( 9.81\right )\left ( 2\right )`

`v=√(185.76)=13.62 m/s`

`Now\ forces\ on\ plate\ are\ weight\left ( Downward\right ) and jet\ force\left ( upward\right )`

equating them

W=
`\left ( \rho Av\right )v`

W=
`10^(3)* (\pi)/(4)\left ( 0.02\right )^2* 13.62^2`

W=58.28 N