Answer: actual yield= 41.4 g
Step-by-step explanation:
Reaction hydrocarbons with excess Oxygen is called Combustion reaction.
To find the actual yield, we need to know thereotical yield.
Theoretical yield:
(24.9 g C2H6/30 g/mol C2H6)X(4 molCO2/2 mol C2H6)X(44 g CO2/1 mol CO2)
= 73.04 g Co2
%yield= observed yiled x100/theoretical yield
Observed yield= %yieldxtheoretical yield/100
= 56.8x73.04/100
= 41.4 g