Question

A swimming pool is circular with a 40-ft diameter. The depth is constant along east-westlines and increases linearly from 2 ft at the south end to 7 ft at the north end. Find the volume of water in the pool.

Answer 1

volume will be equal to 5,655 ft³

Explanation:

diameter of swimming pool = 40 ft

depth increases from east-west lines is from 2 ft to 7 ft

so the average depth of the swimming pool can be calculated by

`D_(avg) = (2+7)/(2)`

hence average depth comes out to be 4.5 m

volume of water in the pool will be equal to the volume of the pool

volume =
`\pi* r^2 * d_(avg)`

=
`\pi* 20^2 * 4.5`

= 5,654.86 ft³

volume will be equal to 5,655 ft³ approximately