Question

Phosphorus reacts with oxygen to form diphosphorus pentoxide: 4 P(s) + 5 O 2(g) -> 2 P 2O 5(s) If 0.97 moles of phosphorus are reacted but 0.12 moles remain after reaction, how many moles of P 2O 5 were produced?

Answer 1

0.425 moles of P₂O₅.

Step-by-step explanation:

As per given balanced equation, four moles of phosphorus reacts with five moles of oxygen to give two moles of P₂O₅.

As given that the initial moles of phosphorus taken = 0.97 moles

moles of phosphorus left after reaction = 0.12 moles

moles of phosphorus reacted = 0.97-0.12 = 0.85 moles

When four moles of P reacts they give two moles of P₂O₅.

when one mole of P will react to give =
`(2)/(4)molP_(2)O_(5)`

0.85 moles of P will react to give =
`(2X0.85)/(4)= 0.425mol`P₂O₅