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What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T1 = 23 ∘C , V1= 1.69×103 L ) to a volume of 3.38×103 L ? Assume no change in pressure or the amount of gas in
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What Celsius temperature, T2, is required to change the volume of the gas sample in Part A (T1 = 23 ∘C , V1= 1.69×103 L ) to a volume of 3.38×103 L ? Assume no change in pressure or the amount of gas in the balloon.

User Balron
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1 Answer

6 votes

Answer:

319.15^{o}C[/tex]

Step-by-step explanation:

When all other variables are constant, we are allowed to use the formula


(T_(2) )/(V_(2) ) = (T_(1) )/(V_(1) ) \\</p><p>Which can be rewritten as T_(2) = (T_(1) V_(2) )/(V_(1) )</p><p>if you make T2 the subject of the formula. This formula is true only if temperature is in Kelvin not degrees Celsius so T1 must be converted to Kelvin</p><p></p><p>Now to calculate T2</p><p>[tex]T_(2)= (296.15K*3.38.10^(3)L )/(1.69.10^(3)L )= 592.3K =
319.15^(o) &nbsp;C

User Zoran Jeremic
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