Question

Identify the Brønsted-Lowry acid, the Brønsted-Lowry base, the conjugate acid, and the conjugate base in each reaction: (a) (CH3)3N(aq)+H2O(l)⇌(CH3)3NH+(aq)+OH−(aq) (b) HNO3(aq)+H2O(l)⇌H3O+(aq)+NO3−(aq)

Answer 1

(a)
`(CH_3)_3NH^+` and
`OH^-` are conjugate acid and base respectively.

(b)
`H_3O^+` and
`NO_3^-` are conjugate acid and base respectively.

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

(a) The given equilibrium reaction is,

`(CH_3)_3N(aq)+H_2O(l)\rightleftharpoons (CH_3)_3NH^+(aq)+OH^-(aq)`

In this reaction,
`H_2O` is an acid that donate a proton or hydrogen to
`(CH_3)_3N` base and it forms
`(CH_3)_3NH^+` and
`OH^-` are conjugate acid and base respectively.

(b) The given equilibrium reaction is,

`HNO_3(aq)+H_2O(l)\rightleftharpoons NO_3^-(aq)+H_3O^+(aq)`

In this reaction,
`HNO_3` is an acid that donate a proton or hydrogen to
`H_2O` base and it forms
`H_3O^+` and
`NO_3^-` are conjugate acid and base respectively.

Answer 2

Answer: A. Bronsted Lowery acid: H2O

Bronsted Lowery base: (CH3)3N

Conjugate acid: (CH3)3NH+

Conjugate base: OH-

B. Acid: HNO3

Base: H2O

Conjugate acid: H3O+

Conjugate base: NO3-

Step-by-step explanation:

Bronsted Lowery acid is proton donor and proton acceptor is base.

And Conjugate acid-base pairs are differed by one proton