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Thirty-five more than the limit of weight (w) in an elevator is greater then 1,050 pounds.

A. Model with an inequality.

B. Solve the inequality.

C. Where would the solution for the inequality be graphed on the number line?

Thirty-five more than the limit of weight (w) in an elevator is greater then 1,050 pounds-example-1

1 Answer

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Answer:

Part A)
w+35 > 1,050

Part B)
w > 1,015\ pounds

Part C) The graph in the attached figure

Explanation:

Part A) Model with an inequality.

Let

w -----> the limit of weight in an elevator

we know that

The inequality that represent this situation is


w+35 > 1,050

Part B) Solve the inequality


w+35 > 1,050

solve for w

Subtract 35 sides


w+35-35 > 1,050-35


w > 1,015\ pounds

All real numbers greater than 1,015 pounds

Part C) Where would the solution for the inequality be graphed on the number line?


w > 1,015\ pounds

The solution is the interval -------> (1,015,∞)

In a number line is the shaded area at right of the number x=1.015 (open circle)

see the attached figure

Thirty-five more than the limit of weight (w) in an elevator is greater then 1,050 pounds-example-1
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