Question

A little help on this math problem?

Answer 1

If you know Heron's formula, this is easy.

`\text{area}=√(s(s-6)(s-10)(s-14))=15\sqrt3`

where
`s=\frac{6+10+14}2=15` is the semiperimeter of the triangle.

The area is also equal to half the product of the base and height of the triangle, which happen to be

`15\sqrt3=\frac{14x}2\implies x=\frac{15\sqrt3}7\approx3.711`

so the answer is B.