Answer:
-i, 5-i
Explanation:
Given that a function f(x) has only real coefficients and also of degree 4.
Since any polynomial with real roots have imaginary roots only with conjugate pairs, we can find other two roots easily
Degree of polynomial = 4
No of roots = 4
GIven roots are i, 5+i
Conjugate of the given roots are -i, 5-i
Hence remaining zeroes of f are -i, 5-i