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Write quadratic equation whose roots are 1 and -3 and whose leading coefficient is 4

User ShivamD
by
5.0k points

2 Answers

3 votes

Answer:

4x^2 + 8x - 12 = 0

Explanation:

A quadratic equation with roots a and b has the equation (x - a)(x - b) = 0.

You roots are 1 and -3.

The equation is

(x - 1)(x - (3)) = 0

(x - 1)(x + 3) = 0

We can multiply it out.

x^2 + 3x - x - 3 = 0

x^2 + 2x - 3 = 0

Since we need the leading coefficient to be 4, we multiply both sides by 4.

4x^2 + 8x - 12 = 0

User Intlsy
by
5.5k points
3 votes

Answer:

4x^2 + 8x - 12 = 0.

Explanation:

We first write it in factor form.

4(x - 1)(x + 3) = 0

4(x^2 + 2x - 3) = 0

4x^2 + 8x - 12 = 0 (answer).

User Kelstar
by
4.5k points
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