Question

Is (0,0) a solution to this system y>=x^2+x-4; y<=x^2+2x+1

Answer 1

yes it is a solution

Explanation:

o>-4

0<1

yes both work out to be equal

Answer 2

It is a solution

Explanation:

Check and see if (0,0) satisfies both inequalities.

The first inequality is:

`y \geqslant {x}^(2) + x - 4`

When we put x=0, and y=0, we get:

`0\geqslant {0}^(2) + 0 - 4`

`\implies0\geqslant- 4`

This part is true.

The second inequality is:

`y \leqslant {x}^(2) + 2 x + 1`

We put x=0 and y=0 to get:

`0 \leqslant {0}^(2) + 2 (0) + 1`

`0 \leqslant 1`

This part is also true.

Since the (0,0) not satisfy both, inequalities, it is a solution.