Question

What is the surface area of the cone? (radius 10in height 26in)

A) 425pi in2
B) 460pi in2
C) 360pi in2
D) 390pi in2

Answer 1

C) 360pi in2

Explanation:

Given:

radius, r= 10in

height, h=26in

surface area of the cone, T.S.A= ?

T.S.A=πrl +πr^2

=π(10)(26) +π(10)^2

=260π+100π

=360π^2 !