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What equation is the inverse of y=x^2+16

User Andarin
by
5.1k points

2 Answers

2 votes

Answer:


y = √(x - 16)

Explanation:


y = {x}^(2) + 16


x = {y}^(2) + 16


x - 16 = {y}^(2)


√(x - 16) = y

User LnNoam
by
5.2k points
2 votes

Answer:

f^-1 (x) = ±sqrt(x-16)

Explanation:

To find the inverse of a function, exchange x and y and solve for y

y=x^2+16

Exchange x and y

x = y^2 +16

Then solve for y

Subtract 16 from each side

x-16 = y^2 +16-16

x-16 = y^2

Take the square root of each side

±sqrt(x-16) = sqrt(y^2)

±sqrt(x-16) = y

The inverse

f^-1 (x) = ±sqrt(x-16)

User Sarmad
by
4.3k points