Question

Both a man and a woman are heterozygous for freckles. Freckles ( F) are dominant over no freckles ( f). What is the chance that their child will have freckles?

Answer 1

75% chance or 3/4

Step-by-step explanation:

If both parents are heterozygous and freckles is a dominant trait (F) then we can denote having no freckles as (f)

Using a punnett square, this will produce the following genotypes of the children:

FF, Ff, Ff and ff.

Therefore, there's a 3 out 4 chance or 75% of the children also inheriting freckles.