Question

Use the quadratic formula to find the solutions to the equation x^2-3x+1=0

Answer 1

The answer is in the picture below! :)

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Answer 2

`x_(1)=(+3+√(5) )/(2)\\\\x_(2)=(+3-√(5) )/(2)`

Explanation:

Using:

`x=\frac{-b+-\sqrt{b^(2)-4*a*c} }{2*a}`

we will have two solutions.

x^2-3x+1=0

So, a=1 b=-3 c=1

`x_(1)=\frac{+3+\sqrt{-3^(2)-4*1*1} }{2*1}\\\\x_(2)=\frac{+3-\sqrt{-3^(2)-4*1*1} }{2*1}`

We have two solutions:

`x_(1)=(+3+√(5) )/(2)\\\\x_(2)=(+3-√(5) )/(2)`