Question

Find the value of k when the value of x is 2/3
kx2 - x - 2 =0

Answer 1

k=6

Explanation:

As stated, x=2/3, so you need to eval in the whole expression given

`k*x^(2) -x-2=0`

which becomes the following>

`k*((2)/(3)) ^(2)-(2)/(3) -2=0\\`

Solving for K gives>

`k=(2+(2)/(3))*(9)/(4)\\k=((9)/(2) +(3)/(2))`

`k=(12)/(2)`