Answer:
(16x^2-1) can be factored over integers so, Option C is correct.
Explanation:
Given: 256x^4y^2-y^2
Factorizing the given expression:
Taking y^2 common
=y^2(256x^4-1)
Using formula: a^2-b^2 = (a-b)(a+b)
=y^2((16x^2)^2-(1)^2)
y^2(16x^2+1)(16x^2-1)
y^2(16x^2+1)((4x)^2-(1)^2)
y^2(16x^2+1)(4x-1)(4x+1)
Since (16x^2-1) can be factored over integers so, Option C is correct.