Question

What is the storage requirement of a bit mappedimage of 800 X 1200 pixels with 24 bits perpixel?

Answer 1

The total storage requirement is 2.74 Megabytes ( 2.74 Mb )

Step-by-step explanation:

The total number of pixels are

`800*1200 = 960000\, pixels`

As there are 24 bits per pixel,

the total number of bits are calculated as

`800 * 1200 * 24 \, bits = 23,040,000 \, bits`

As,
`1\, Byte = 8 \,bits , \, 1\, Kilobyte\, = 1,024\, Bytes, \, 1 \, Megabyte \, = 1,048,576 Bytes`

The total storage requirement is 2.74658203125 Megabytes.