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What is the common ratio between successive terms in the sequence?
27, 9, 3, 1, 1927

User Matandked
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1 Answer

5 votes

Answer:

1/3

Explanation:

Tn = a × r^(n - 1)

T1 = a × r^(1 - 1) = a × r^0 = a = 27

T2 = a × r^(2 - 1) = a × r = 9 (equation 1)

To find the common ratio, put a as 27 in equation 1

27 × r = 9

r = 9/27 = 1/3

User Hahakubile
by
5.4k points