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A sample of gas in a balloon has an initial temperature of 22 ∘C and a volume of 1820 L . If the temperature changes to 84 ∘C , and there is no change of pressure or amount of gas, what is the new volume, V2, of the gas?

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Answer:

The new volume of the gas is 1955.65 L.

Step-by-step explanation:

Initial temperature of the gas in the balloon =
T_1= 22°C = 295.15 K

Initial volume of the the gas
V_1= 1820 L

Final temperature of the gas in the balloon
T_2 = 84°C = 317.15 K

Final volume of the the gas =
V_2=?

Under constant pressure and amount of gas, the gas will follow Charles' law:


(V_1)/(T_1)=(V_2)/(T_2) (Constant pressure)


V_2=(1820 L* 317.15 K)/(295.15 K)=1955.65 L

The new volume of the gas is 1955.65 L.

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