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If we measure the temperature of a blackbody to be about 300 K (a typical air temperature in Florida), at what wavelength would this blackbody's intensity have its maximum, and where in the electromagnetic spectrum is this wavelength?

User Melly
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1 Answer

3 votes

Answer:

9.66 x 10^-6 m

Step-by-step explanation:

Use the Wein's displacement law


\lambda _(m)* T = b

Where, b is the Wein's constant

b = 2.898 x 10^-3 meter-kelvin

So, λm x 300 = 2.898 x 10^-3

λm = 9.66 x 10^-6 m

User Ekad
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